The figure below consists Of two rectangles , one triangles and one semicircle.

The diameter of the semi-circle, FC = 10 cm. The two rectangles ABCD and EDFG have the Same dimensions. The area of the right angled triangle FDC = 24 sq. cm and 
FD = 6 cm. 
What is the TOTAL AREA of the figure given above? 
A. (42 + 10  π ) sq.cm
B. (120+25 π ) sq. cm
C. (120+25/2 π ) sq.cm 
D. (96 +25/2 π ) sq.cm 

Dear Student,

Area of Semicircle = πr22Area of Semicircle = π×522 = 25π2Area of rectangle = length × breadthArea of triangle = 12×base×perpendicularArea of triangle DCF is given as 24 cm2 , Now, 12×base×perpendicular = 2412×base×6 = 24base = 243 = 8 cmSo, DC =8 cmSince the two rectangles are same,Area of rectangle ABCD and EDFG =2× 6×8 =2 × 48 cm2 =96 cm2Total Area = Area of rectangle ABCD and EDFG +Area of Semicircle+Area of triangleTotal Area =96 + 25π2 +24 = 192+25π+482Total Area =240+25π2 = 120 + 25π2 cm2Hence option C is correct.

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