Ramesh bought two boxes for Rs 1300.He sold one box at a profit of 20% and the other box at a loss of 12%.If the s.p.of both boxes in the same ,find the c.p. of each box.....ans ts.....

Given: Ramesh bought two boxes for Rs 1300. Let the cost price (C.P.) of one box be Rs x.

Then the C.P. of other box will be Rs (1300 – x).

Now profit on first box = 20% of x

 

 

and loss on other box = 12% of (1300 – x)

 

 

But S.P. of both box are equal

 

Hence, C.P. of first box is Rs 550 and C.P. of other box is Rs 750.

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ITS VERY EASY

IF PROFIT

CP=SP*100/200+P

IF LOSS

CP=SP*100/200-L

LET THE SP = X

1ST BOX CP=X*100/200+20

=100X/220=5X/11

2ND BOX CP=X*100/200-12

=100X/188=25X/47

A.T.Q

CP1+CP2=1300

5X/11+25X/47=1300

510X/517=1300

X=1300*517/510

X=1317.84

CP OF 1ST BOX=1317.84*5/11

=599.02(APPROX.)

CP OF 2ND BOX=1317.84*25/47

=700.98(APPROX.)

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