If the volume of the cube is 64b^3, then what is the surface area of the cube?

Dear student, Volume of cube = (side)³ => (side)³ = 64b³ Cube rooting both sides, => side = 4b [cube root of 64b³ = 4b] Surface area of cube •Total surface area = 6×(side)² •Lateral surface area = 4×(side)² Thus, as per required, it is most probably of total surface area = 6×(4b)² = 6×16b² = 96b² If lateral surface area is required, then it will be 64b² I hope this was helpful !
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