divide [a] square+6a+5 bya+1

Factorizing a2 + 6a + 5 by splitting the middle term
 a2 + 6a + 5
= a2 + 5a + a + 5  (note that 6 = 5 + 1 and 5 = 5×1)
= a(a + 5) + 1(a + 5)
= (a + 5)(a + 1)
Hence we can see that a + 1 is a factor of a2 + 6a + 5
OR
When a2 + 6a + 5 is divided by a + 1, the quotient left is 'a +5' and remainder is 0. 

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