Construct a rectangle ABCD whose diagonal BD= 4.6 cm and the angle between the diagonals is 60 degree

Answer :

Given :  Diagonal of rectangle ABCD , BD  =  4,6 cm we know diagonals of rectangle are equal to each other and bisect each other . 

So, we follow these steps to construct our required rectangle ABCD : 

Step 1 :  Draw a line BD  =  4.6  cm

Step 2 :  Find mid point of BD , OB  =  OD  =  2.3 cm 

Step  3 :  Now we take any radius ( Less than OD )  and center " O "  draw an arc that intersect our line OD at " P "  , With same radius and center " P "  draw another arc that intersect our previous arc at " Q " .

Step 4 : Join OQ and extend it on both side of line BD we get line " XY " .

Step 5 : We take radius of 2.3 cm and center " O "  draw arc on line XY on both side of line BD these arcs intersect line XY at A and C .

Step 6 :  Join AB , BC , CD and  DA we get required rectangle ABCD .

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