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1. From the sum of 4b2 + 5bc, -2b2 – 2bc – 2z2 and 2bc + 4c2, subtract the sum of 5b2 – c2 and -3b2 + 2bc + c2.

2. The sum of two expressions is 3x2 + 2xy – y2. If one of them is 2x2 + 3y2, find the other.

3. Subtract 2a2b – 3b2 from 3a2 – 5ab2 + 2b2 and subtract your result from the sum of the two expressions 3ab2 + 5b2 – 2a2b and a2b + 5a2 – 3ab2.

4. In the year 1999, the average cost of a car could be modeled by the equation C = -8t2 + 9500 where t is the number of years since 1999. By the year 2008 the average cost had changed, so it could be modeled by the equation C = -15t2 + 10000.Find the difference in the average costs for a car between 2008 and 1999

5. If the length of a rectangle in terms of x is 7x2 + 5x – 6, and its width is 6x2 + 4x + 2, what is the perimeter of this rectangle?

6. How much should a + 2b – 3c be increased to get 3a?

$2)LettheotherexpressionbeA\phantom{\rule{0ex}{0ex}}Accordingtoquestion,\phantom{\rule{0ex}{0ex}}A+2{x}^{2}+3{y}^{2}=3{x}^{2}+2xy-{y}^{2}\phantom{\rule{0ex}{0ex}}\Rightarrow A=3{x}^{2}+2xy-{y}^{2}-\left(2{x}^{2}+3{y}^{2}\right)\phantom{\rule{0ex}{0ex}}\Rightarrow A=3{x}^{2}+2xy-{y}^{2}-2{x}^{2}-3{y}^{2}\phantom{\rule{0ex}{0ex}}\Rightarrow A={x}^{2}-4{y}^{2}+2xy\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}6)Leta+2b-3cbeincreasedtoAtoget3a\phantom{\rule{0ex}{0ex}}\Rightarrow a+2b-3c+A=3a\phantom{\rule{0ex}{0ex}}\Rightarrow A=3a-a-2b+3c\phantom{\rule{0ex}{0ex}}\Rightarrow A=2a-2b+3c\phantom{\rule{0ex}{0ex}}$

For remaining question kindly post in separate thread

Regards

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